You can start with the form
∆y(x -x1) -∆x(y -y1) = 0
Here, we have
∆y = 11-(-3) = 14
∆x = -3-1 = -4
and we can choose (x1, y1) = (1, -3). This gives
14(x -1) -(-4)(y -(-3)) = 0
14x +4y -2 = 0
All these terms have a common factor of 2 that we can remove. Adding 1 to the result puts it in standard form:
7x +2y = 1
The line x = -11.4 is perpendicular to the x-axis and contains point
(-11.4 , 12.8)
Step-by-step explanation:
Let us revise the equations of the vertical lines and horizontal lines
- The vertical line is a line parallel to y-axis
- The x-coordinates of all points lie on the line are equal
- The equation of the vertical line basses through point (a , b) is x = a
- The horizontal line is a line parallel to x-axis
- The y-coordinates of all points lie on the line are equal
- The equation of the horizontal line passes through point (a , b) is y = b
- The vertical line and the horizontal line are perpendicular to each other when intersect each other
∵ The line is perpendicular to the x-axis
∴ The line is a vertical line
∴ The equation of the line is x = a, where a is the x-coordinate
of any point lies on the line
∵ The line contains point (-11.4 , 12.8)
∵ The x-coordinate of the point is -11.4
∴ a = -11.4
∴ The equation of the line is x = -11.4
The line x = -11.4 is perpendicular to the x-axis and contains point
(-11.4 , 12.8)
Learn more:
You can learn more about the linear equation in brainly.com/question/13168205
#LearnwithBrainly
Answer:
Dilations which reduce or enlarge an object. Translations which move the object from one part on the graph to another. I have also learned about how to construct a perpendicular bisector.
Step-by-step explanation:
