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2 years ago

What kind of mixture is the gravel at the bottom of the fish tank?

Physics

2 answers:

kotegsom [21]2 years ago

7 0

Hey there! I’m Raegan and i believe the answer is “Rock”. Thank you for your time.

adoni [48]2 years ago

6 0

Answer:

rock

Explanation:

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Which type of force can act through empty space?

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D. Magnetism this is shown by the planet's magnetic pull on moons and space debris.

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2 years ago

If two organisms evolve in response to each other, which evolutionary pattern is demonstrated

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2 years ago

Read 2 more answers

A 20-lb force acts to the west while an 80-lb force acts 45° east of north. The magnitu 80 lb 70 lb 067 lb 100 lb

natulia [17]

Answer:

option C

Explanation:

given,

force act on west = 20 lb

force act at 45° east of north = 80 lb

magnitude of force = ?

∑ F y = 80 cos 45⁰

F y = 56.57 lb

magnitude of forces in x- direction

∑ F x = -20 + 80 sin 45⁰

= 36.57 lb

net force

F = $\sqrt{F_x^2+F_y^2}$

F = $\sqrt{56.57^2+36.57^2}$

F = 67.36 lb≅ 67 lb

hence, the correct answer is option C

4 0

2 years ago

Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. A 9.4 kg gibbon

Katarina [22]

Answer:

upward force acting = 261.6 N

Explanation:

given,

mass of gibbon = 9.4 kg

arm length = 0.6 m

speed of the swing

net force must provide

$F_{branch} + F_{gravity}=F_{centripetal}$

force of gravity = - mg

$F_{branch}=F_{centripetal}-F_{gravity}$

= $\dfrac{mv^2}{r} + mg$

= $m(\dfrac{3.4^2}{0.6} +9.8)$

=9 x 29.067

= 261.6 N

upward force acting = 261.6 N

7 0

2 years ago

An unstable particle at rest spontaneously breaks into two fragments of unequal mass. The mass of the first fragment is 3.00 10-

kirill [66]

Answer:0.478 c

Explanation:

Given

mass of lighter Particle $(m_1)=3\times 10^{-28} kg$

mass of heavier Particle $(m_2)=1.51\times 10^{-27} kg$

speed of lighter particle $(v_1)=0.834 c$

Let speed of heavier particle $=v_2$

and Momentum of the particle is given by

$P=\frac{mv}{\sqrt{1-(\frac{v}{c})^2}}$

$P_1=\frac{m_1v_1}{\sqrt{1-(\frac{v_1}{c})^2}}$

$P_1=\frac{3\times 10^{-28}\times 0.834 c}{\sqrt{1-(\frac{0.834 c}{c})^2}}$

$P_1=8.219\times 10^{-28} kg c$

$P_2=\frac{m_2v_2}{\sqrt{1-(\frac{v_2}{c})^2}}$

as momentum is conserved therefore $P_1=P_2$

$8.219\times 10^{-28} kg c=\frac{1.51\times 10^{-27}\times v_2}{\sqrt{1-(\frac{v_2}{c})^2}}$

$v_2=0.478 c$

3 0

2 years ago