We start with the more complicated side which is the left side, and show that, on using some trigonometric identities, we will get the term on the right side .

$\frac{sin \theta + tan \theta}{1+cos \theta}$

Using Quotient identity for tangent function, we will get

$\frac{sin \theta+ \frac{sin \theta}{cos \theta}}{1+cos \theta}$

$\frac{sin \theta cos \theta + sin \theta}{cos \theta(1+cos \theta)}$

Taking out sine function from the numerator

$=\frac{sin \theta(1+cos \theta)}{cos \theta(1+cos \theta)}$

Cancelling the common term of numerator and denominator

$=\frac{sin \theta}{cos \theta} = tan \theta$

7 0

2 years ago

20 POINTS IF ANSWERED CORRECTLY AND BRAINLIEST PLEASE HELP ME (07.06 LC)

chubhunter [2.5K]

3.5z=2.25z-4.25+6.25
1.25z=2
z=1.6. As a result, this equation have one solution. Hope it help!

6 0

2 years ago

Read 2 more answers

The rate at which energy is used is called <br> work, voltage, power, or amperage.

SSSSS [86.1K]

Answer:

The rate at which energy is used is called power.

Step-by-step explanation:

5 0

2 years ago