Jennifer has a coupon for 25% off her entire meal of $17.89. What is the discount?
2 answers:
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Answer:
(a) section A = 18 , section B= 288
(b) 16 times greater
Step-by-step explanation:
To find average rate of change use formula
g(x)= 6(4)^x
Section A is from x = 0 to x = 1
a=0 , b=1
Average rate of change for section A is
Section B is from x = 2 to x = 3
a=2 , b=3
Average rate of change for section B is
Part B :
Average rate of change of section B is 288
Average rate of change of section A is 18
288 / 18 = 16
288 is 16 times greater than 18
So section B is 16 times greater than section A
Because g(x) is an exponential function that increases faster when x value increases
The explanation of the problem is as shown in the figure.
<span>A blimp ⇒⇒⇒ point A
</span><span>stadium 1 ⇒⇒⇒ point B
</span><span>stadium 2 ⇒⇒⇒ point C
height of the blimp ⇒⇒⇒ AD = 1600
</span>depression angle of <span>stadium 1 ⇒⇒⇒ ∠y = </span><span>71.7°
</span>depression angle of <span>stadium 2 ⇒⇒⇒ ∠x = 25.2°
distance between </span><span><span>the two stadiums ⇒⇒⇒ d
DC = AD * tan (90° - x) = 1600 * tan( 90° - 25.2° )
DB = AD * tan (90° - y) = 1600 * tan( 90° - 71.7° )
</span></span>∴ d = DC - DB
= 1600 * [ tan( 90° - 25.2° ) - <span>tan( 90° - 71.7° ) ]
= 2,871 </span><span>meters
</span>∴ The correct choice is option (D)
<span>A blimp ⇒⇒⇒ point A
</span><span>stadium 1 ⇒⇒⇒ point B
</span><span>stadium 2 ⇒⇒⇒ point C
height of the blimp ⇒⇒⇒ AD = 1600
</span>depression angle of <span>stadium 1 ⇒⇒⇒ ∠y = </span><span>71.7°
</span>depression angle of <span>stadium 2 ⇒⇒⇒ ∠x = 25.2°
distance between </span><span><span>the two stadiums ⇒⇒⇒ d
DC = AD * tan (90° - x) = 1600 * tan( 90° - 25.2° )
DB = AD * tan (90° - y) = 1600 * tan( 90° - 71.7° )
</span></span>∴ d = DC - DB
= 1600 * [ tan( 90° - 25.2° ) - <span>tan( 90° - 71.7° ) ]
= 2,871 </span><span>meters
</span>∴ The correct choice is option (D)