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2 years ago

How do mass and speed affect kinetic energy?

2 answers:

6 0

The mass affects the kinetic energy because the more the mass the more energy is given to the object and the speed affects by making it go faster and longer, so whenever speed goes up so does energy.

Nikolay [14]2 years ago

4 0

Here is your answer:

Kinetic energy is when an object or person is moving.

Ex: A car going down the street.

Mass effects kinetic energy because mass is weight and weight will make an object go slower which lowers the kinetic energy and rises the potential energy (that's when a object is at rest or not moving)

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Transfer of heat through objects touching source

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3 years ago

Read 2 more answers

Suppose you are standing on top of a hemisphere of radius r and you kick a soccer ball horizontally such that it has velocity v.

Ksivusya [100]

$|v| =\sqrt{ G \cdot M / r}$ , where

$M$ the mass of the planet, and
$G$ the universal gravitation constant.

Explanation:

Minimizing the initial velocity of the soccer ball would minimize the amount of mechanical energy it has. It shall maintain a minimal gravitational potential possible at all time. It should therefore stay to the ground as close as possible. An elliptical trajectory would thus be unfavorable; the ball shall maintain a uniform circular motion as it orbits the planet.

Equation 1 (see below) relates net force the object experiences, $\Sigma F$ to its orbit velocity $v$ and its mass $m$ required for it to stay in orbit :

$\Sigma F = m \cdot v^{2} / r$ (equation 1)

The soccer ball shall experiences a combination of gravitational pull and air resistance (if any) as it orbits the planet. Assuming negligible air resistance, the net force $\Sigma F$ acting on the soccer ball shall equal to its weight, $W = m \cdot g$ where $g$ the gravitational acceleration constant. Thus

$\Sigma F = W = m \cdot g$ (equation 2)

Substitute equation 2 to the left hand side of equation 1 and solve for $v$ ; note how the mass of the soccer ball, $m$ , cancels out:

$m \cdot g = \Sigma F = m \cdot v^{2} / r \\ v^{2} = g \cdot r \\ |v| = \sqrt{g \cdot r} \; (|v| \ge 0)$ (equation 3)

Equation 4 gives the value of gravitational acceleration, $g$ , a point of negligible mass experiences at a distance $r$ from a planet of mass $M$ (assuming no other stellar object were present)

$g = G \cdot M/ r^{2}$ (equation 4)

where the universal gravitation constant $G = 6.67408 \times 10^{-11} \cdot \text{m}^{3} \cdot \text{kg}^{-1} \cdot \text{s}^{-2}$

Thus

$\begin{array}{lll}|v| &=& \sqrt{g \cdot r}\\ & =&\sqrt{ G \cdot M / r}\end{array}$

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2 years ago

State Newton’s third law of motion.

bagirrra123 [75]

Answer:every force has an equal and oppisite reaction. meeaning if you punch a wall wwith 50lbs of force the wall pushes back on your hand with 50 lbs of force

Explanation:

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3 years ago

The best place to look for crabs is between the high tide and low tide zones (the tidal flat). knowing this, would you expect to

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The best answer for this question is generally the best period to look for crabs is for the duration of the full moon, this is as a result of most invertebrates being nocturnal and being more effortlessly spotted and being fascinated to light sources.

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2 years ago

What are the directions of movement for the Sagittarius, frontal, transverse planes ?

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Answer:

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2 years ago