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2 years ago

James ran 1 mile in 8 minutes in the morning and 3.5 miles in 28 minutes in the evening

Mathematics

1 answer:

alexdok [17]2 years ago

5 0

cool, what's the question?

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Help?? I could really use it

Lynna [10]

Answer:

16.5 m

Step-by-step explanation:

The triangle shown in the figure is a right triangle, so we can use the Pythagoreas Theorem.

a² + b² = c²

a² + 32² = 36²

a² + 1024 = 1296

a² = 272

a = √272

a = 16.5

Answer: 16.5 m

4 0

1 year ago

Highest common factor of 24,32,40

s344n2d4d5 [400]

Answer:

Step-by-step explanation:

5 0

1 year ago

The ratio of boys to girls in a class is 7:5. There are 36 students in the class. How many

Whitepunk [10]

Answer:

There would be 15 girls and 21 boys

7 0

2 years ago

Read 2 more answers

A student ran out of time on a multiple choice exam and randomly guessed the answers for 2 problems. Each problem had 5 answer c

frozen [14]

So if there are 5 choices and only one is correct, there is a 1/5 chance of being correct. since there was 2 questions, you need to multiply 1/5 by 1/5 to get 2/25 of getting both questions correct.

i hope this helps!!

3 0

2 years ago

Explain why f(x) = x^2+4x+3/x^2-x-2 is not continuous at x = -1.

liberstina [14]

Answer:

The value of x = -1 makes the denominator of the function equal to zero. That is why this value is not included in the domain of f(x)

Step-by-step explanation:

We have the following expression

$f(x) = \frac{x^2+4x+3}{x^2-x-2}$

Since the division between zero is not defined then the function f(x) can not include the values of x that make the denominator of the function zero.

Now we search that values of x make 0 the denominator factoring the polynomial $x^2-x-2$

We need two numbers that when adding them get as a result -1 and when multiplying those numbers, obtain -2 as a result.

These numbers are -2 and 1

Then the factors are:

$(x-2) (x + 1)$

We do the same with the numerator

$x^2+4x+3$

We need two numbers that when adding them get as a result 4 and when multiplying those numbers, obtain 3 as a result.

These numbers are 3 and 1

Then the factors are:

$(x+3)(x + 1)$

Therefore

$f(x) = \frac{(x+3)(x+1)}{(x-2)(x+1)}$

Note that $\frac{(x+1)}{(x+1)}=1$ only if $x \neq -1$

So since $x = -1$ is not included in the domain the function has a discontinuity in $x = -1$

3 0

2 years ago