Answer:
A Hercules Beetle is 6.97 inches larger than A ladybug
Step-by-step explanation:
A hercules beetle is 7 inches long while a ladybug is about 0.03 cm long when subtracting these two you will get a grand total of 6.97.
Answer:
<u>1.16 m (approximately)</u>
Step-by-step explanation:
Let x be the width of the path.
Total area = (5+2x)(3+2x) = 39
Expand and simplify
4x²+ 16x+15-39 = 0
4x² + 16x - 24 = 0
Simplify
x² + 4x -6 = 0
Rational factoring does not work, so use quadratic formula
x = +/- sqrt(10) -2
= 1.16 or -5.16 (reject)
= <u>1.16 m (approximately)</u>
<span>D) Greater than 8 because you are multiplying by a number greater than 1.
8 * 2 1/3 = 8 * 7/3 = 56/3 = 18.67
& we know, 18.67 > 8
Hope this helps!</span>
470000 is the most reasonable
well, we know it's a line, and to get the equation of any line all we need is two points, let's pick two from the table hmmmm say let's use (-3 , -7) and (3 , 11)
