The equation of motion is
s(t) = (1/2)a·t² +v₀·t +s₀
where a is the acceleration, v₀ is the initial velocity, and s₀ is the initial position.
For t in seconds and s(t) in feet, your values make this equation be
s(t) = 5t² -20t +8
Step-by-step explanation:
To find a rat of change (ROC) you take the two numbers and the two prices and subtract them to make a ratio<u>:</u>
<u>_</u><u>_</u><u>_</u><u>_</u><u>6</u><u>-</u><u>3</u><u>_</u><u>_</u><u>_</u><u>_</u><u>_</u> = <u>_</u><u>_</u><u>_</u><u>3</u><u>_</u><u>_</u><u>_</u>
$2.56-$2.44 = $2.12
The reduce to the lowest number (the 3 to a 1)
<u>_</u><u>_</u><u>3</u><u>_</u><u>_</u><u>_</u> = <u>_</u><u>_</u><u>_</u><u>1</u><u>_</u><u>_</u>
$2.12 $0.71
The ROC is $0.71
Answer:
We have the equation:
(ax^2 + 3x + 2b) - (5x^2+bx-3c)= 3x^2 - 9
First, move all to the left side.
(ax^2 + 3x + 2b) - (5x^2+bx-3c) - 3x^2 + 9 = 0
Now let's group togheter terms with the same power of x.
(a - 5 - 3)*x^2 + (3 - b)*x + (2b + 3c + 9) = 0.
This must be zero for all the values of x, then the things inside each parenthesis must be zero.
1)
a - 5 - 3 = 0
a = 3 + 5 = 8.
2)
3 - b = 0
b = 3.
3)
2b + 3c + 9 = 0
2*3 + 3c + 9 = 0
3c = -6 - 9 = -15
c = -15/3 = -5
Then we have:
a = 8, b = 3, c = -5
a + b + c = 8 + 3 - 5 = 6
+ 2 × 5
To evaluate apply the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)
Parentheses
There are none for this steps so go on to the next step
Exponent:
81
so...
81 + 2 × 5
Multiplication:
81 + 2 × 5
2 × 5
10
so...
81 + 10
No division in this equation so skip this step and go to the next one
Addition:
81 + 10
91
Hope this helped!
~Just a girl in love with Shawn Mendes
Y: x-1 that is the answer. I think so.