Answer:
Quieres ser mi novia.. Hermosa.. MI estrella fugaz
Step-by-step explanation:
❤️❤️❤️❤️❤️❤️:-):-):-):-)amorsito...,,,,,,, - - - - ////
The expected length of code for one encoded symbol is
where is the probability of picking the letter , and is the length of code needed to encode . is given to us, and we have
so that we expect a contribution of
bits to the code per encoded letter. For a string of length , we would then expect .
By definition of variance, we have
For a string consisting of one letter, we have
so that the variance for the length such a string is
"squared" bits per encoded letter. For a string of length , we would get .
Answer:
10+8+2.5+8+6+2.5=37 .
ok you are understand or bot
120/4=30. Remember its widthxlength. if you forget ask your teacher or look online for more help. Good luck.
Answer:
ur down 24 pts.
Step-by-step explanation:
3×8=24
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