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2 years ago

8

Please help. I will give 16 points.

1 answer:

Allushta [10]2 years ago

4 0

Answer:

(4, -2)

Step-by-step explanation:

if you do process of elimination you find that 'a' doesn't work out but 'b' will . . . substitute -2 for 'y' and 4 for 'x' and see if the equation is true

-2 = -3/4(4) + 1

-2 = -3 + 1

-2 = -2

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Find the 10th term of geometric sequence 3,15,75,375

Bess [88]

Answer:

Step-by-step explanation:

In a geometric sequence, the next term is a constant times the previous term. This constant is determined by dividing the second term by the first, here giving 5. The remaining terms are checked to see that each is 5 times the previous. 75 is 15×5, 375 is 75×5.

Alternately, the nth term is first term times k^(n-1).

Here, that's 3×5^(10-1), 3×5^9=5859375

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2 years ago

You are saving up money to buy a new ipad. You begin with $25, and are able to save $40 each month. Write an

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567

Step-by-step explanation:

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2 years ago

Questions (no partial grades if you don't show your work) 1. In a group of 6 boys and 4 girls, four children are to be selected.

mariarad [96]

Answer:

Total number of ways will be 209

Step-by-step explanation:

There are 6 boys and 4 girls in a group and 4 children are to be selected.

We have to find the number of ways that 4 children can be selected if at least one boy must be in the group of 4.

So the groups can be arranged as

(1 Boy + 3 girls), (2 Boy + 2 girls), (3 Boys + 1 girl), (4 boys)

Now we will find the combinations in which these arrangements can be done.

1 Boy and 3 girls = $^{6}C_{1}\times^{4}C_{3}=6\times4$ =24

2 Boy and 2 girls= $^{6}C_{2}\times^{4}C_{2}=\frac{6!}{4!\times2!}\times\frac{4!}{2!\times2!}=15\times6=90$

3 Boys and 1 girl = $^{6}C_{3}\times^{4}C_{1}=\frac{6!}{4!\times2!}\times\frac{4!}{3!}=\frac{6\times5\times4}{3 \times2} \times4=80$

4 Boys = $^{6}C_{4}=\frac{6!}{4!\times2!} =\frac{6\times 5}{2\times1}=15$

Now total number of ways = 24 + 90 + 80 + 15 = 209

7 0

2 years ago

Mrs. Smith has 12 times as many markers as colored pencils. The total number of markers and colored pencils is 78. How many mark

yanalaym [24]

The answer is 930, because 78 multiply 12 is 930.

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2 years ago

Read 2 more answers

3q(p-q)+2r(p-q)-S(q-p)<br> Can u solve it step by step

Artyom0805 [142]

Answer:

-3q² + 3qp + 2rp - 2rq + Sq - Sp

Step-by-step explanation:

first part

3q(p-q) = 3qp - 3q²

second part

2r(p-q) = 2rp - 2rq

third part

S(q-p) = Sq - Sp

then we put it all together

3qp - 3q² + 2rp - 2rq + Sq - Sp

in the right place possibly

-3q² + 3qp + 2rp - 2rq + Sq - Sp

8 0

1 year ago