X=25 jjjjjjjjjjjjjjjjjjjjjjjjjjjj
seperable differential equations will have the form
what you do from here is isolate all the y terms on one side and all the X terms on the other
just divided G(y) to both sides and multiply dx to both sides
then integrate both sides
once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it
In your problem,
so all you need to integrate is
y < - 8 or y > 4
inequalities of the form | x | > a always have solutions of the form
x < - a or x > a
we have to solve
y + 2 < - 6 or y + 2 > 6
y + 2 < - 6 ( subtract 2 from both sides )
y < - 8
or
y + 2 > 6 ( subtract 2 from both sides )
y > 4
these can be combined using interval notation
y ∈ (- ∞, - 8 ) ∪ (4, ∞ )
As a check
substitute chosen values of x from each interval
y = - 10 : | - 10 + 2 | = | - 8 | = 8 > 6 this is true
y = 12 : | 12 + 2 | = | 14 | = 14 > 6 which is also true
I found this --The first step to dividing fractions is to find the reciprocal (reverse the numerator and denominator) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. Finally, simplify the fractions if needed.
Answer:
c
Step-by-step explanation:
