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2 years ago

Grey ran 2.4 times as many miles as Emory. If Emory ran 2.08 miles, how many miles did grey run?

Mathematics

2 answers:

V125BC [204]2 years ago

5 0

Answer:

4.992

Step-by-step explanation:

Hey there !!! 

to find the answer to this problem you multiply the number of miles that grey ran to the number of miles that Emory ran:

2.4 * 2.08 = 4.992

Hope it helped !!

have a wonderful day

CaHeK987 [17]2 years ago

3 0

Answer:

If Grey ran 2.4 times as many miles as Emory, then 2.08 x 2.4 = 4.992

Step-by-step explanation:

4.992

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3 years ago

What is 2226 ÷ 53?????

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2 years ago

Read 2 more answers

A sociologist wishes to estimate the percentage of the United States population living in poverty. What size sample should be ob

andriy [413]

Answer:

a) We need a sample size of at least 705.

b) We need a sample size of at least 1692.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

a) If she uses 1999 estimate of 11.8% obtained from the Current Population Survey.

We need a sample of size at least n

n is found when $M = 0.02, \pi = 0.118$ .

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.645\sqrt{\frac{0.118*0.882}{n}}$

$0.02\sqrt{n} = 1.645\sqrt{0.118*0.882}$

$\sqrt{n} = \frac{1.645\sqrt{0.118*0.882}}{0.02}$

$(\sqrt{n})^{2} = (\frac{1.645\sqrt{0.118*0.882}}{0.02})^{2}$

$n = 704.08$

Rounding up

We need a sample size of at least 705.

b) She does not use any estimate.

Same thing as above, we just use $\pi = 0.5$ when do not use any estimate.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.645\sqrt{\frac{0.5*0.5}{n}}$

$0.02\sqrt{n} = 1.645\sqrt{0.5*0.5}$

$\sqrt{n} = \frac{1.645\sqrt{0.5*0.5}}{0.02}$

$(\sqrt{n})^{2} = (\frac{1.645\sqrt{0.5*0.5}}{0.02})^{2}$

$n = 1691.2$

Rounding up

We need a sample size of at least 1692.

4 0

2 years ago

Which equation represents a circle with a center at (2,-3) and a radius of 11

Verdich [7]

Answer:

x^2-4x+y^2+6y-108=0

Step-by-step explanation:

$The- equation- of- circle- with -center- at- (h,k) -and -a -radius- of- r -is: \\(x-h)^2 +(y-k)^2 = r^2\\h = 2 , \\ k = -3\\r = 11\\(x-2)^2+(y-(-3))^2 = 11^2\\(x-2)^2+(y+3)^2 = 121\\x^2-4x+4 +y^2+6y+9 = 121\\x^2 -4x+y^2+6y+4+9=121\\x^2 -4x+y^2+6y+13=121\\x^2 -4x+y^2+6y=121-13\\x^2 -4x+y^2+6y= 108\\x^2 -4x+y^2+6y-108 = 0$

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3 years ago

Find the volume of the figure.

jeka57 [31]

Hello from MrBillDoesMath!

Answer:

1283.3

Discussion:

Volume of figure =

volume of cone + volume of cylinder =

(1/3) Pi r^2 h + Pi r^2 h =

(1/3) Pi (7)^2* 7 + Pi (7)^2 * 6 =

Pi * 7^2 ( (1/3) *7 + 6) = => using PI is approx 22/7

(22/7) * 7^2 ( 7/3 + 6) =

(22/7)* 49 (25/3) = 1283.3

Thank you,

MrB

3 0

2 years ago