Answer:
The density is equal to the weight divided by the volume:
The paperweight weights 300 grams.
Step-by-step explanation:
The density of the paperweight can be calculated knowing the weight and the volume of this paperweight.
The density is equal to the weight divided by the volume:
We know that the density of this paperweight is 1.5 grams per cm3, and its volume is 200 cm3.
We can use the formula of the density to calculate the weight:
The paperweight weights 300 grams.
Answer: The approximate value of x is -3.396
Step-by-step explanation:
Given:
Now,to find the value of x.
Use logarithm rule:
We have,
Now,
Using value of: and we get,
on simplify:
Adding 1 both the sides, we get
Therefore, the approximate value of x for the equation is -3.396.
=
Step-by-step explanation:
Answer:
k = –10
Step-by-step explanation:
From the question given above, the following data were obtained:
f(x) = x³ – 6x² – 11x + k
Factor => x + 2
Value of K =?
Next, we shall obtained the value of x from x + 2. This is illustrated below:
x + 2 = 0
Collect like terms
x = 0 – 2
x = –2
Finally, we shall determine the value of k as illustrated below:
f(x) = x³ – 6x² – 11x + k
x = –2
Thus,
f(–2) = 0
x³ – 6x² – 11x + k = 0
(–2)³ – (–2)² – 11(–2) + k = 0
–8 – (4) + 22 + K = 0
–8 – 4 + 22 + K = 0
10 + k = 0
Collect like terms
k = 0 – 10
k = –10
Thus, the value of k is –10
Hello!
x² - 4x + 6 = 9 <=>
<=> x² - 4x + 6 - 9 = 0 <=>
<=> x² - 4x - 3 = 0 <=>
<=> x = -(-4)±√(-4)²-4×1×(-3)/2×1 <=>
<=> x = 4±√16+12/2 <=>
<=> x = 4±√28/2 <=>
<=> x = 4±2√7/2 =>
=> x = 4+2√7/2 and x = 4-2√7/2 =>
=> x = 2+√7 and x = 2-√7
The equation has two solutions.
Good luck! :)
Answer:
5%
Step-by-step explanation:
You sum the lost excess weight: 50% + 20% + 25% = 95%. Meaning that she lost 95% of the excess weight. It remained just 5% to lose.