The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
<h3>How to determine the number of real zeros?</h3>
The equation of the function is given as:
Expand the function
Reorder the terms
Factor the expression
Factor out x -1
Expand
Factorize
Factor out x + 2
The function has been completely factored and it has 3 linear factors
Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
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Answer:
B
Step-by-step explanation:
I added all of then and then subtracted 47 from the 50.
Answer:
702 r4
Step-by-step explanation:
Ⓗⓘ ⓣⓗⓔⓡⓔ
4918/7=702 r4
You could do it with either a calculator or by simple division.
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