9514 1404 393
Answer:
0.4, 0.004, 0.004
Step-by-step explanation:
The "what" in each case is found by dividing the target value by 10. That is accomplished by moving the decimal point one place to the left.
4/10 = 0.4 ⇒ 10 times 0.4 = 4
0.04 and .04 are exactly the same value, so the last two on your list are the same:
0.04/10 = 0.004 ⇒ 10 times .004 = 0.04
Answer:
c) 452.4 square feet
Step-by-step explanation:
HOPE THIS HELPS, MARK AS BRAINLIEST PLEASE NOT THE FILE VIRUS EXPLOITER
Answer:
19ft
Step-by-step explanation:
Given the height of a ball above the ground after x seconds given by the quadratic function y = -16x2 + 32x + 3, we can find the maximum height reached by the ball since we are not told what to look for.
The velocity of the ball is zero at maximum height and it is expressed as:
V(x) = dy/dx
V(x) = -32x+32
Since v(x) = 0
0 = -32x+32
32x = 32
x = 32/32
x = 1s
Get the height y
Recall that y = -16x² + 32x + 3.
Substitute x = 1
y = -16(1)²+32(1)+3
y = -16+32+3
y = -16+35
y = 19ft
Hence the maximum height reached by the ball is 19ft
Answer:
d=4/5
Step-by-step explanation:
2(5+d)=14
10+5d=14
5d=4
d=4/5
Answer:
t= 3.1 years
Step-by-step explanation:
A = A_0 e kt
Half life(1/2) = 26 yrs
1/2 = 1_0 e^k.26
ln(1/2) = ln(e^26k)
26k. ln(e) = ln(1/2)
k = 1/26* ln(1/2)
k = -0.0267
A = A_0 e^kt
0.92 = 1.e^(-0.0267)t
ln(0.92) = ln(e^(-0.0267)t
-0.0267t .ln(e) = ln(0.92)
t = ln(0.92) / -0.0267
t = 3.122
t = 3.1years (approximate to 1 d.p)