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2 years ago

12

a shoe box in the shape of right rectangular prism has base that mesure 7 inches and is 5 inches high what is the volune of the

shiee box cubic inches

1 answer:

Andrew [12]2 years ago

7 0

Answer:

35

Step-by-step explanation:

If the base is 7 that would be the length times width and then you multiply that by 5 which gets you 35.

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Plz help!!<br> Consider the given right triangle.

aalyn [17]

Answer:

b = 8

c = 16

Step-by-step explanation:

From the given right triangle,

a = $8\sqrt{3}$ , m(∠B) = 30°

By applying sine rule in the given triangle,

cos(B) = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

cos(B) = $\frac{BC}{AB}$

cos(30°) = $\frac{8\sqrt{3}}{c}$

$\frac{\sqrt{3} }{2}= \frac{8\sqrt{3} }{c}$

c = 16

Further we apply tangent rule,

tan(B) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$

tan(30°) = $\frac{b}{a}$

$\frac{1}{\sqrt{3}}=\frac{b}{8\sqrt{3} }$

b = 8

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2 years ago

Please helppp!! Round to the nearest hundredths

densk [106]

Answer:1385.44mm sq

Step-by-step explanation: surface area of a circle = pi x radius squared

3.142 x 21 squared

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2 years ago

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Martha Jones received a $540 discount loan to purchase a new sewing machine. The loan was offered at 12.5% for 90 days. Find the

Ede4ka [16]

16.88

523.12

at least for the question i got

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2 years ago

What is equation created from the sqrt(x+2)+2))^2

Naddika [18.5K]

Answer:

x + 4√(x + 2) + 6

Step-by-step explanation:

All we need to do is expand by using FOIL (First, Outside, Inside, Last):

x + 2 + 2√(x + 2) + 2√(x + 2) + 4

Then we combine like terms to get our final answer:

x + 2 + 4√(x + 2) + 4

x + 4√(x + 2) + 6

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2 years ago

(1+tan^2 A)cot A/cosec^2 A= tanA

Rufina [12.5K]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

1 + tan²A = sec²A , secA = $\frac{1}{cosA}$ , cosecA = $\frac{1}{sinA}$ , cotA = $\frac{cosA}{sinA}$ , tanA = $\frac{sinA}{cosA}$

Consider the left side

$\frac{(1+tan^2A)cotA}{cosec^2A}$

= $\frac{sec^2AcotA}{cosec^2A}$

= $\frac{\frac{1}{cos^2A}(\frac{cosA}{sinA}) }{cosec^2A}$

= $\frac{\frac{1}{cosAsinA} }{\frac{1}{sin^2A} }$

= $\frac{1}{cosAsinA}$ × sin²A

= $\frac{sinA}{cosA}$

= tanA = right side , thus proven

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2 years ago