Explanation:
It is given that,
Diameter of the circular loop, d = 1.5 cm
Radius of the circular loop, r = 0.0075 m
Magnetic field,
(A) We need to find the current in the loop. The magnetic field in a circular loop is given by :
I = 32.22 A
(b) The magnetic field on a current carrying wire is given by :
r = 0.00238 m
Hence, this is the required solution.
Answer:
The answer to your question is C
Explanation:
acceleration is a vector quantity because it has both magnitude and direction
Power (watts) = work done (joules) ÷ time (seconds)
power (watts) = 1000J ÷ 20s
power (watts) = 50w
Answer:
50m/s.
Explanation:
Let's take acceleration as A and speed as S:
A = 5m/s²
S = A × 10s = 5 × 10 = 50m/s
The answer is 50m/s.
Answer:
each rotation of the smaller wheel will show 84.382-75.3982=8.9838 inches more than the actual distance
Explanation:
d = Diameter of the wheel
The distance traveled in one rotation of the wheel is the circumference of the wheel
When diameter is 24 inches
Therefore, each rotation of the smaller wheel will show 84.382-75.3982=8.9838 inches more than the actual distance