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2 years ago

62.52=27.39+t this is 7th grade math! plsss help!!1

Mathematics

1 answer:

Tju [1.3M]2 years ago

6 0

Answer:

Hope it helps you friend

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Find the vector with initial point p (4, 3) and terminal point q (–9, –4).

lana66690 [7]

-9 -4 = -13
-4 - 3 = -7

vector is <-13, -7>

6 0

2 years ago

How many years would it take to make $500 interest on a 12000 investment at 3% per year

padilas [110]

Answer:

$t=1.4\ years$

Step-by-step explanation:

we know that

The simple interest formula is equal to

$I=P(rt)$

where

I is the Final Interest Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

$t=?\\ P=\$12,000\\ I=\$500\\r=3\%=3/100=0.03$

substitute in the formula above

$500=12,000(0.03t)$

solve for t

$500=360t$

$t=500/360$

$t=1.4\ years$

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2 years ago

Solve for x: 5x+2-10x=22

sasho [114]

Answer:

X=-4

Step-by-step explanation:

5x-10x=22-2

-5x=20

x=-4

7 0

2 years ago

Eitan randomly selected volcanoes to travel to and study. After traveling, he had seen 13 cinder cone volcanoes, 18 shield volca

larisa [96]

Answer:

Probability of selecting one volcano in the world on which to conduct an extensive study is given by

$\frac{1}{37}$

Step-by-step explanation:

Since we have given that

Number of cinder cone volcanoes = 13

Number of shield volcanoes = 18

Number of strato volcanoes = 6

Total number of volcanoes is given by

$13+18+6\\\\=37$

So, Probability of getting one volcano in the world on which to conduct an extensive study is given by

$\frac{\text{Number of favorable outcomes}}{\text{ Total number of outcomes}}\\\\=\frac{1}{37}$

Hence, Probability of selecting one volcano in the world on which to conduct an extensive study is given by

$\frac{1}{37}$

8 0

2 years ago

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Which is the simplified form of the expression ((p squared) (q Superscript 5 Baseline)) Superscript negative 4 Baseline times ((

Alexus [3.1K]

Answer:

$q^{-30}$

Step-by-step explanation:

Given the expression:

$((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}$

First, we open the outer brackets

$=(p^{2X-4}) (q ^{5X-4})X (p ^{-4X-2}) (q^{5X-2})\\\\=(p^{-8}) (q ^{-20})X (p ^{8}) (q^{-10})\\\\$Next, we can collect like terms\\\\=p^{-8}Xp ^{8}Xq ^{-20}Xq ^{-10}\\\\$Applying addition law of indices\\\\=p^{-8+8}Xq^{-20+(-10)}\\\\=p^0 X q^{-30}\\\\=1 X q^{-30}\\\\=q^{-30}$

Therefore:

$((p^2) (q ^5)) ^{-4} X ((p ^{-4}) (q^5)) ^{-2}=q^{-30$

8 0

3 years ago

Read 2 more answers