Here you go. Do you think that you could help me with my question
5a – 10b = 45
5a – 10(3) = 45
5a – 30 = 45
+30 +30
5a = 75/5
<span>a = 15</span>
<h3>
Answer: -19, -15, -9, -1, 9 (choice A)</h3>
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Explanation:
If we plug in x = -2, then we get,
y = x^2 + 7x - 9
y = (-2)^2 + 7(-2) - 9
y = 4 - 14 - 9
y = -10 - 9
y = -19
So x = -2 leads to y = -19. The answer is between A and D.
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If you repeat those steps for x = -1, then you should get y = -15
Then x = 0 leads to y = -9
x = 1 leads to y = -1
Finally, x = 2 leads to y = 9
The outputs we get are: -19, -15, -9, -1, 9 which is choice A
Choice D is fairly close, but we won't have a second copy of -15, and we don't have an output of -19.
Answer:
3.
Step-by-step explanation:
4$ = 1 pack
(think: what times 4 is 12? 3! so we need to muliply both sides of the equal sign by 3, so we can turn the 4 into a 12. Remember, what you do to on side, you must do to the other. )
4$ = 1 pack
*3 *3
12$ = 3 packs
so your answer is 3.
Let x be the number of minutes Peg and Larry used their phones. So their costs can be written as:
Cost of Peg's Phone usage = 25 + 0.25x
Cost of Larry's Phone usage = 35 + 0.20x
We are to find when the Peg's phone will be more than Larry's phone. We can set up the inequality as:
25 + 0.25x > 35 + 0.20x
Re-arranging the inequality
0.25x - 0.20x > 35 - 25
0.05x > 10
x > 10/0.05
x > 200
Thus, Pag's phone will cost more if the number of minutes of phone usage is more than 200
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