There are a couple of different approaches you can use for this. Here's one.
1. Determine how many digits repeat. (There is just one repeating digit.)
2. Call your number x. Multiply x by 10 to the power of the number of digits found in step 1.
3. Subtract the original number, then solve for x.
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If you recognize that 0.333... (repeating) is 1/3, then you know that 0.0333... (repeating) is 1/10×1/3 = 1/30. Add that to 0.8 = 4/5 and you get
... 4/5 + 1/30 = 24/30 + 1/30 = 25/30 = 5/6
Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Step-by-step explanation:
Let,
Weight of one large bead = x
Weight of one small bead = y
According to given statement;
12x+8y=88 Eqn 1
5x+2y=25 Eqn 2
Multiplying Eqn 2 by 4
Subtracting Eqn 1 from Eqn 3
Dividing both sides by 8
Putting x=1.5 in Eqn 1
Dividing both sides by 8
Weight of one large bead is 1.5 grams and weight of one small bead is 8.75 grams.
Keywords: linear equation, elimination method
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