Answer:
1st pic) 17.8
2nd pic) 16.8
3rd pic) 9.1
4th pic) 13.5
Step-by-step explanation:
<u>1st pic:</u>
(write equation) Cos 27 (cos 27 = 0.89) =
(new equation) 0. 89 =
(multiply 20 on both sides) 0.89 x 20 = x 20
(solve) 17.8 = x
<u>2nd pic:</u>
(write equation) tan 40 (tan 40 = 0.84) =
(new equation) 0.84 =
(multiply 32 on both sides) 0.84 x 20 = x 20
(solve) 16.8 = x
<u>3rd pic:</u>
(write equation) cos 55 (cos 55 = 0.57) =
(new equation) 0.57 =
(multiply 16 on both sides) 0.57 x 16 = x 16
(solve) 9.1 = x
<u>4th pic:</u>
(write eqaution) tan 42 (tan 42 = 0.90) =
(new equation) 0.90 =
(multiply 15 on both sides) 0.90 x 15 = x 15
(solve) 13.5 = x
Answer:
(-3, -4).
Step-by-step explanation:
-4x + y = 8
x - 5y = 17 Multiply this by 4:
4x - 20y = 68 Add this to the first equation:
-19y = 76
y = 76/-19
y = -4.
Plug this into the second equation:
x - 5(-4) = 17
x = 17 - 20
x = -3.
CHECK this result in equation 1:
-4(-3) + -4 = 8
12 - 4 = 8
8 = 8 <------ OK.
Answer:
The answer is C. n = 3
Step-by-step explanation:
I got this answer by using the butterfly method. I multiplied 3 and 2 and got 6. Then take 6 and divide it by 2 and you get 3.
So therefore, n = 3
Please mark brainliest if this helped.
Answer:
4V = 3U
Step-by-step explanation:
The final cost of a sale item is determined by multiplying the price on the tag by 75%.
Let us assume that the final cost of the sale item is V and the price on the tag is given by U.
Then the equation that best describes the function that represents the situation is
⇒ 4V = 3U (Answer)
Answer:
- b/a
- 16a²b²
- n¹⁰/(16m⁶)
- y⁸/x¹⁰
- m⁷n³n/m
Step-by-step explanation:
These problems make use of three rules of exponents:
In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)
__
1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.
__
2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.
__
3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.
__
4. This works the same way the previous problem does.
__
5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.