A volume of 0.550 L of gas is contained at 23.0°C. What is the new volume of the gas if it is heated to 57.°C. Assume that the p
ressure of the gas remains constant. Work must be shown to earn credit.
1 answer:
Answer:
0.61 L
Explanation:
T1 = 23.0 +273 = 296K
T2 = 57+273 = 330 K
V2 = (V1×T2)/T1
V2 = (0.55 × 330)/296
V2 = 0.61 L
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