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anzhelika [568]

2 years ago

15

If the function h is defined by h(x)=

lign="absmiddle" class="latex-formula">-3x+5,then h(2x+1)=

1 answer:

harkovskaia [24]2 years ago

3 0

Given:

The function is:

$h(x)=x^2-3x+5$

To find:

The value of $h(2x+1)$ .

Solution:

We have,

$h(x)=x^2-3x+5$

Putting $x=2x+1$ , we get

$h(2x+1)=(2x+1)^2-3(2x+1)+5$

$h(2x+1)=(2x)^2+2(2x)(1)+(1)^2-3(2x)-3(1)+5$

$h(2x+1)=4x^2+4x+1-6x-3+5$

On combining like terms, we get

$h(2x+1)=4x^2+(4x-6x)+(1-3+5)$

$h(2x+1)=4x^2-2x+3$

Therefore, the required function is $h(2x+1)=4x^2-2x+3$ .

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2x^2=9-3x <br> Find the factors

d1i1m1o1n [39]

Answer:

x = -3, $\frac{3}{2}$

Step-by-step explanation:

The given quadratic equation is: $2x^2 = 9 - 3x$

This can be written as: $2x^2 + 3x - 9 = 0$

To solve a quadratic equation of the form $ax^2 + bx + c = 0$ we use the formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Here, a = 2; b = 3; c = - 9

Therefore, the roots of the equation are:

$x = \frac{- 3 \pm \sqrt{9 - 4(2)(-9)}}{2(2)}$

$\implies x = \frac{-3 \pm \sqrt{81}}{4}$

$\implies x = \frac{-3 \pm 9}{4}$

We get two values of 'x', viz.,

x = $\frac{-3 + 9}{4}$ and $\frac{- 3 - 9}{4}$

$\implies x = \frac{6}{4} \hspace{5mm} \& \hspace{5mm} \frac{-12}{4}$

⇒ x = -3, 3/2

Since the factors of the quadratic equation is asked, we write it as:

(x + 3)(x - $\frac{3}{2}$ ) = 0

because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $\frac{3}{2}$ to see that this indeed is the given quadratic equation.

5 0

2 years ago

What is the lateral area of a right cylinder if the radius of the base is 12 mm and the altitude of the cylinder is 5 times the

lakkis [162]

The lateral area of a cylinder is given by:
Area=πrl+2πr^2
radius,r=12 mm
length,l=5*12=60mm
therefore the lateral area will be:
Area=π*12*60
Area=2,261.95 mm^2
The area of the bases will be:
A=2*π*12^2=904.78 mm^s
The lateral area will be:
2,261.95+904.78
=3,166.73
=3167 mm^2

5 0

2 years ago

2. explain what is meant by (distribution) transparency and give examples of different types of transparency.

konstantin123 [22]

The phenomena of hiding distribution characteristics in a system from applications and users is known as distribution transparency. Access transparency, location transparency are some examples.

<h3>Define the term (distribution) transparency?</h3>

Distributed databases have the attribute of distribution transparency, which keeps consumers from knowing the internal workings of the distribution.

The DDBMS designer has the option of replicating table fragments, storing them at several locations, and fragmenting tables.
There are numerous distribution methods. Systems that need a wide range of management systems to pinpoint the source of resources, a product, or a service delivery process from the end user.
Typically, the distributor, seller, or producer is responsible for maintaining transparency to track the many points at which resources, goods, or services are delivered.
Accounting supplied by any intermediary company in the product, service, or resource flow is, of course, the usual approach to determine the degrees of value added through distribution management.

Thus, access transparency, location transparency are some examples of the (distribution) transparency.

To know more about the transparency, here

brainly.com/question/14590546

#SPJ4

5 0

6 months ago

Please answer this question

VashaNatasha [74]

Answer:

i think 1

remember like this: y=mx+b

m is slope

b is y intercept

8 0

2 years ago

Read 2 more answers

In art class, Arthur has created a triangle painting 1/5 of his painting is purple. He decided he wants to Paint 4/8 of the purp

babymother [125]

$\frac{1}{10}$ part of the whole painting is gold colored.

<u>Solution:</u>

Given that , In art class, Arthur has created a triangle painting $\frac{1}{5}$ of his painting is purple.

He decided he wants to Paint $\frac{4}{8}$ of the purple area gold

We have to find what fraction of the whole painting will be painting?

Now, $\frac{1}{5}$ part of whole painting is purple

And, $\frac{4}{8}$ part of the purple area is gold ⇒ $\frac{4}{8}$ part of the $\frac{1}{5}$ part of whole painting is gold

$\text { Then, fraction of gold color }=\frac{4}{8} \times \frac{1}{5}=\frac{1}{2} \times \frac{1}{5}=\frac{1}{10}$

Hence, $\frac{1}{10}$ part of the whole painting is gold colored.

4 0

2 years ago