Multiples of 10.
Is that what you are asking?
Answer:
x = 15
Step-by-step explanation:
Since the triangles are similar then the ratios of corresponding sides are equal, that is
BC/DC = EC/AC , substitute values
3x×5/32 - 5x-5/56 ( cross- multiply )
56(3x - 5) = 32(5x - 5) ← distribute and simplify both sides
168x - 280 = 160x - 160 ( subtract 160x from both sides )
8x - 280 = - 160 ( add 280 to both sides )
8x = 120 ( divide both sides by 8 )
x = 15
(1+r)^5=137.76/100
1+r=(137.76/100)^(1/5)
R=(137.76/100)^(1/5))-1
We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.
To solve this problem we will use permutations.
We know that formula for permutations is given as
On substituting the given values in the formula we get,
Therefore, there are 39270 ways in which prizes can be awarded.
3.14?
or do you want more digits?
3.141592653589793238462643383279502884197169399375105820974944592307816406286<span> </span>