2 years ago

The ratio of the lengths of 3 squares of different sizes is 2:4:7. If the length of the biggest

Mathematics

1 answer:

Slav-nsk [51]2 years ago

8 0

9514 1404 393

Answer:

Step-by-step explanation:

The largest square is 7-2 = 5 ratio units larger than the smaller square. Hence, each ratio unit stands for (10 cm)/5 = 2 cm. The side length of the smaller square is 2(2 cm) = 4 cm. The perimeter is 4 times that: 16 cm.

The perimeter of the smallest square is 16 cm.

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(ab^2 x -b^4a^3)^2<br><br> What is the answers

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Answer:

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

Step-by-step explanation:

Given the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

solving the expression

$\left(ab^2\:x\:-b^4a^3\right)^2$

$\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a-b\right)^2=a^2-2ab+b^2$

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so the expression becomes

$=\left(ab^2x\right)^2-2ab^2xb^4a^3+\left(b^4a^3\right)^2$

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Thus,

$\left(ab^2x-b^4a^3\right)^2:\quad a^2b^4x^2-2a^4b^6x+a^6b^8$

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