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2 years ago

8

Mrs. Wilson tells you that the next test is worth 100 points and contains 38 problems. Multiple-choice questions are worth 2 poi

nts each and word problems are worth 5 points. How many of each type of question are there

1 answer:

Colt1911 [192]2 years ago

7 0

Answer:

30 mcq and 8 word problems

plz mark as brainliest

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Solve the equation.<br><br>5/7=10/x+2

skelet666 [1.2K]

Answer:

$x=-\frac{70}{9}$

Step-by-step explanation:

Isolate the variable by doing operations to both sides of the equation.

The work is shown below:

$\frac{5}{7} =\frac{10}{x} +2\\\\\frac{5}{7} - 2=\frac{10}{x} +2 - 2\\\\-\frac{9}{7} = \frac{10}{x}\\\\ -\frac{9}{7}*x = \frac{10}{x}*x\\\\ -\frac{9}{7}x = 10\\\\ -\frac{9}{7}x * (-\frac{7}{9})= 10 * (-\frac{7}{9}) \\\\x=-\frac{70}{9}$

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2 years ago

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how many ounces of water must be added 100 oz. of 60% iodine to produce a 55% solution ? round your answer to the nearest hundre

algol [13]

Answer:

10 ounces

Step-by-step explanation:

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1 year ago

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10 POINTS IF SOMEONE COULD HELP ME WITH THIS!! :(

rewona [7]

Answer:

Your answer is B) Elevator 1 is 16 feet above ground level, and elevator 2 is 25 feet below ground level.

Mark as brainliest if it's correct!

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2 years ago

Someone please help this is due tomorrow;(

nevsk [136]

Sorry if my handwriting sloppy.

I showed all of it step by step.

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2 years ago

Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi

Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}$

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

$P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483$

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

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2 years ago