Answer:
25
Step-by-step explanation:
Answer:
the answer is d to the problem
Answer:
Step-by-step explanation:
To solve this problem you need the function
h(t) = -16t2 + v0t + h0
where t = time
v0 is the initial velocity, which in our case is 0
h0 = initial height, which in our case is 256
h(t) = 0 since we want to know when the ball will hit the ground.
0 = -16 t2 + 256
And we can solve for t
If we rearrange the terms we see that this is a difference of 2 squares
0 = 256 - 16t2
0 = (16-4t)(16+4t)
Setting each factor = 0
16-4t=0 16+4t=4
t = 4 t = -4
The second solution is discarded as time cannot be negative.
So the ball will hit the ground in 4 seconds.
Answer:
Step-by-step explanation:
Remember that the range is the set of all y-values. Thus, since the minimum of the function is y=-1, then our range is . In interval notation, we use brackets to show what's included and parentheses to show what's not included.
A) 4(25-3y)+5y=9
100-7y=9
91=7y
y=13
(-14,13)
b) 14-x=x-10
2x=24
x=12
(12,14)
c) 4x=12
(3,7)
d) 18.5x+10.4y=200
x+y=130
