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2 years ago

How many moles of H₂O can be produced when 5.5 moles of CO₂ is produced? C₂H₄ + 3 O₂ --> 2 CO₂ + 2 H₂O

Chemistry

1 answer:

mrs_skeptik [129]2 years ago

6 0

Answer:

5.5 mol H2O

Explanation:

Given over what you need and then mole ratio of coefficients in the balanced equation then cross multiply and do PEMDAS for that, and then you got your answer :) hope this helped.

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2. Name each of the following ionic compounds A. K2O B. Cacl2. C. Mg3N2 D. NaCIO E. KNO3

Ludmilka [50]

A. Potassium oxide
B. Calcium chloride
C. Magnesium nitride
D. Sodium hypochlorite
E. Potassium nitrate

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2 years ago

How many moles of Pb(no3)3 will be required to react with 0.64 mole of KCl?

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2 years ago

Have a tour in your kitchen pick five (5) food products having nutrition facts

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Answer:

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4 0

1 year ago

Pls tell me how to solve this!

Anna35 [415]

Answer:

12 seconds

Explanation:

Time taken by 50cm³ of oxygen to diffuse from pinhole

= 1 minute = 60 seconds

⠀

$\textsf{ Rate of oxygen} \sf (O_2) = \frac{50}{60}$

⠀

Let time taken by 50cm³ of hydrogen to diffuse from pinhole = t seconds

⠀

$\textsf {Rate of hydrogen } \sf(H_2) = \frac{50}{t}$

⠀

According to the formula

$\sf \frac{Rate \: of \: hydrogen(H_2)}{Rate \: of \: oxygen(O_2) } = \sqrt{ \frac{Molar \: mass \: of \: O_2}{Molar \: mass \: of \: H_2} }$

⠀

$\large \sf \frac{50}{t} \div \frac{50}{60} = \sqrt{ \frac{\cancel{32}\small 16}{\cancel2} } \\ \\ \sf \large \frac{ \cancel{50}}{t} \times \frac{60}{ \cancel{50}} = \sqrt{16} \\ \\ \sf \large \frac{60}{t} = 4 \\ \\ \sf \large \frac{ \cancel{60} \: \small12}{ \cancel4} = t \\ \\ \large \underline{ \boxed{ \tt t = 12 \: seconds}}$

⠀

<h3>Henceforth, the time taken by 50cm³ of hydrogen to diffuse is 12 seconds. </h3>

⠀

<h2>Thank you!</h2>

8 0

1 year ago

Which of the following is the weakest of the attractive forces that bond atoms together?

kirill [66]

Well you havent given examples but dispersion forces is probably the answer? although this bonds molecules so if its between metallic ionic and covalent i think its covalent

3 0

2 years ago