I don't remember what is a extraneous solution, but i hope it helps
For a system of equations such as this, add both of the equations together. The d values will cancel each other out, making 2e=-4. This means that e=-2. If you plug this into one of the equations, you will have d + (-2) = 1. Isolate the variable by adding -2 to both sides: d=3. Written in the format described above (d,e), your answer is (3, -2).
275 beacues if u and 50 five times it would of been 250 but u an the five two the 50 and u and 55 five times and u get 275
Answer:
Yes
Step-by-step explanation:
Domain: {-6, 3, 4, 5}
Range: {2, 4, 6}
This relation is a function.
