Ask question

Ask question

All categories

2 years ago

15

1/A ball is dropped from the top of a building. After 3 seconds, its speed is measured to be 29.4 m/s. Calculate the acceleratio

n of the dropped ball.
2/ How fast will the ball be going after 4 seconds?

1 answer:

AleksAgata [21]2 years ago

7 0

Answer:

9.8

Explanation:

You might be interested in

PLEASE PLEASE HELP! this is on newton’s 2nd law! i will award 20 points and make you brainliest! ASAP PLEASE! ;)

horsena [70]

Answer: The correct answer is B

Explanation: The string is pulling right and the string is unraveling causing it to accelerate left

5 0

2 years ago

Read 2 more answers

Dust settling out of the air<br> chemical change or physical change

mars1129 [50]

Physical changes: melting, evaporating, and condensation. This is a physical change.

7 0

2 years ago

Read 2 more answers

What is the weight of an astronaut who has a mass of 90 kg on the moon? (Note: acceleration due to gravity of the moon is 1.62 N

motikmotik

Answer:

W = 145.8 [N]

Explanation:

To solve this problem we must remember that weight is defined as the product of mass by gravity, in this case lunar gravity.

W = m*g

where:

m = mass = 90 [kg]

g = gravity acceleration = 1.62 [kg/m²]

W = 90*1.62

W = 145.8 [N]

8 0

2 years ago

Why the bulb of thermometer in cylindrical

crimeas [40]

I'm not accurately sure if you're asking for why the bulb of a thermometer is in a cylindrical shape. So let me continue. The shape of the which is thin and cylindrical in the shape is the increase of the effect of mercury in the tube to rise and fall depending on the contact temperature.

4 0

2 years ago

The vertical force f acts downward at A on the two membered frames. Determine the magnitude of the two components of F directed

galben [10]

Answer:

The magnitude will be "353.5 N". A further solution is given below.

Explanation:

The given values is:

F = 500 N

According to the question,

In ΔABC,

⇒ $\angle BCA = (90-30)$

⇒ $=60^{\circ}$

then,

⇒ $\angle BAC=(180-45-60)$

⇒ $=75^{\circ}$

Now,

The corresponding angle will be:

⇒ $\angle FAC=60^{\circ}$

⇒ $\angle FAB=70+60$

⇒ $=135^{\circ}$

Aspect of F across the AC arm will be:

= $F\times cos(60)$

On putting the values of F, we get

= $500\times (.5)$

= $200 \ Newton$

Component F along the AC (in magnitude) will be:

= $F\times cos(135)$

= $500\times (-.707)$

= $-353.5 \ N \$

4 0

2 years ago