A jar contains 6 blue gumballs, 4 yellow gumballs, and 8 red gumballs. What is the probability of choosing a yellow gumball and
then a red gumball if the first gumball is placed back into the jar before the second is chosen?
1 answer:
Answer:
2/9 or 22.22% and 4/9 or 44.44%
Step-by-step explanation:
6+4+8=18 4/18=2/9 8/18=4/9
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No, he doesn't it would be 5 cents over the amount of money he has.