the formula to find the diagonal would be
a^2+b^2=c^2
3^2+4^2= 9+16=25
the square root of 25 is 5
5^2=25
so your diagonal is 5 ft
Answer:
oNE DAY A TRIANGLE SPLIT IN SO MANY DIFFERENT PEICES VBUT SUDDENLY ONE DAY THEY ALL CAME BACK.....
Step-by-step explanation:
(2n+1)(2n-1)(n+5)
=(4n^2+2n-2n-1)(n+5)
=(4n^2-1)(n+5)
=4n^3-n+20n^2-5
4n^3+20n^2-n-5
Answer:
Step-by-step explanation:
Let's take one of the equations and solve for x. I'll take the first one.
Divide by 13.
Now replace x in the second equation.
Distribute -8
Break down the fraction.
Subtract
Subtract 6y
Combine like terms;
Solve;
Keep solving;
Multiply by the negative reciprocal of the fraction next to y.
On the right side; 13 and 13 become 1. 300/30 = 30/3 = 10
After having found y, replace it in any of the equations to find x.
<span>5/8 divided 2
(5/8) / 2 = 5/8 * 1/2 = 5/16
Hope it helps</span>