This problem is about the rate of the current. It's important to know that refers to the quotient between the electric charge and the time, that's the current rate.
Where Q = 2.0×10^−4 C and t = 2.0×10^−6 s. Let's use these values to find I.
<em>As you can observe above, the division of the powers was solved by just subtracting their exponents.</em>
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<h2>Therefore, the rate of the current flow is 1.0×10^2 A.</h2>
In the frame of reference of anybody in the car.
Answer: the golf ball with smooth surface would hit the ground first.
Jusitification:
An analysis of forces show two vertical forces acting on the golf balls.
1) one force is the weight (mg) which is vertical downward
2) the other force is the drag force exerted by the air on the golf balls, and it is vertical upward.
3) the drag force opposes the weight, so the acceleration downward is determined by the difference of the weiight and the drag force, until the balls reach the terminal speed (when the drag force equals the weight).
4) the drag force depends on the shape and area of the object falling. Being the surface of one ball smooth implies that the drag force will be less than the one on the other ball.
5) less drag force implies that the terminal velocity of the smooth ball will he higher, ant then it will hit the ground first.
Answer:
Force = -91.7 Newton
Explanation:
Given the following data;
Mass = 47 kg
Time = 4.1 seconds
Initial velocity = 8 m/s
Since the object comes to a stop, its final velocity would be equal to zero.
To find the force required to bring it to stop;
First of all, we would determine the acceleration of the object;
Mathematically, acceleration is given by the equation;
Substituting into the equation;
Acceleration, a = -1.95 m/s²
Next, we would determine the force required to bring the object to stop;
Force = -91.65 ≈ 91.7 Newton