14 and 11 are it dimensions
Hope this helps!
We have the following equation:
2 (x-3) ^ 2 + 10 = 82
We must clear x.
We pass the constant terms to one side of the equation:
2 (x-3) ^ 2 = 82 - 10
2 (x-3) ^ 2 = 72
(x-3) ^ 2 = 72/2
(x-3) ^ 2 = 36
Square root to both members:
x-3 = +/- root (36)
x-3 = +/- 6
The solutions are:
x1 = 6 + 3 = 9
x2 = -6 + 3 = -3
Answer:
x1 = 9
x2 = -3
Answer:
c
Step-by-step explanation:
=16
![\sqrt[3]{16}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B16%7D)
