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2 years ago

Use Pythagorean theorem to find the missing length. (round to tenth if necessary) IS

Mathematics

1 answer:

sertanlavr [38]2 years ago

7 0

11.7

Formula: a^2 + b^2 = c^2

so substitute the numbers like this:

10^2 + 6^2 = c^2

both 10^2 and 6^2 are perfect squares:

10 × 10= 100 and 6 × 6= 36

100 + 36= c^2

add:

100 + 36 =

136 = c^2

now in order to get rid of the squared, you put it into a radical:

√136 = √c^2

note: whatever you do on one side, you do to the other

it's easier to use the calculator for this so put √136 and you're gonna get 11.66

since it's asking you to round it to the nearest tenth:

11.66 = 11.7

sorry if the explanation is kinda long ✋ i tried explaining it better in the end but i failed

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Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

$a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10$

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

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And finally we can calculate the angle between the vectors like this:

$cos \theta = \frac{ab}{|a| |b|}$

And the angle is given by:

$\theta = cos^{-1} (\frac{ab}{|a| |b|})$

If we replace we got:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

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