2 years ago

24 N of force is applied to stop a 12 kg bowling ball. What is the acceleration on the ball?

Mathematics

1 answer:

Nimfa-mama [501]2 years ago

3 0

Answer:

2 m/s^2

Step-by-step explanation:

f=ma

24 N = 12 kg * a

a = 2 m/s^2

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<h3>The Amplitude </h3>

The Amplitude can be calculated as

$amplitude = \frac{max + min}{2}\\ amplitude = \frac{10+14}{2} = 12$

<h3>The Vertical Shift</h3>

The vertical shift is the average difference between the maximum and minimum.

$Vertical Shift = \frac{Max - Min}{2} = \frac{14-10}{2} = 2$

For b value

The Time Period will be twice the distance between max and min.

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<h3>The Period</h3>

The period is calculated as

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Learn more on time period and amplitude here;

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1 year ago

Convert 0.04 to a fraction in lowest terms. *

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1/25

Step-by-step explanation:

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3 years ago

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