<u>Answer:</u>
<u>333×2+999-999÷2= 333</u>
<u>Step-by-step explanation:</u>
Answer:
k = 79
Step-by-step explanation:
3(k-99) = -60
(k-99) = -20
k= -20+99
k=79
Step-by-step explanation: For - 3 1/2 you would place between the -4 and -3 in the middle
The other one I don't know because I can't see the denominator but if you tell me I could
Answer:
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
Suppose a sample of 1067 floppy disks is drawn. Of these disks, 74 were defective.
This means that
80% confidence level
So , z is the value of Z that has a pvalue of , so .
The lower limit of this interval is:
The upper limit of this interval is:
The 80% confidence interval for the population proportion of disks which are defective is (0.059, 0.079).