Question

If a color-blind female wants to have children with a normal male, what is the probability one of their sons could be color blind? (Only the sons should be factored into this calculation...) One of their daughters color blind? One of their daughters a carrier? In addition, determine the genotypes of the two parents.​

Answer 1

Answer:

• Mother´s genotype: X⁻ X⁻  
• Father´s genotype: X⁺ Y
• Son´s genotype: X⁻ Y
• Daughter´s genotype: X⁺X⁻
• The probability of having a color-blind son, X⁺Y, is 2/2 = 100%
• The probability of having a color-blind daughter, X⁻X⁻,  is 0%
• The probability of having a carrier daughter, X⁺X⁻, is 2/2 = 100%

Explanation:

Due to technical problems, you will find the complete explanation in the attached files

   

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