Answer:
a) a = 4.9 m / s², N = 16.97 N and b) F = 9.8 N
Explanation:
a) For this exercise we will use Newton's second law, we write a reference system with the x axis parallel to the plane, see attached, in this system the only force we have to break down is weight, let's use trigonometry
sin 30 = Wx / W
cos 30 = Wy / W
Wx = W sin30
Wy = W cos 30
Let's write the equations on each axis
X axis
Wx = ma
Y Axis
N- Wy = 0
N = Wy = mg cos 30
N = 2.0 9.8 cos 30
N = 16.97 N
We calculate the acceleration
a = Wx / m
a = mg sin 30 / m
a = g sin 30
a =9.8 sin 30
a = 4.9 m / s²
b) For the block to move with constant speed, the acceleration must be zero, so the force applied must be equal to the weight component
F -Wx = 0
F = Wx
F = m g sin 30
F = 2.0 9.8 sin 30
F = 9.8 N
Answer:
Explanation:
Since the pulley has a mass concentrated on its rim, the pulley can be considered as a ring.
The moment of inertia of a ring is
The mass on the left is heavier, that is the pulley is rotating counterclockwise.
By Newton's Second Law, the net torque is equal to moment of inertia times angular acceleration.
Here, the net torque is the sum of the weight on the left and the weight on the right.
Applying Newton's Second Law gives the angular acceleration
The relation between angular acceleration and linear acceleration is
Then, the linear acceleration of the masses is
Answer:
0.333 m/s
Explanation:
avg speed= (total distance)/(total time)
10m/30s
0.333 m/s
Speed = (distance covered) / (time to cover the distance).
The speed of anything that covers 42 meters in 7 seconds is
(42 meters) / (7.0 seconds)
= (42 / 7.0) (meters/second)
= 6.0 m/s .
