The Factorization of 121b⁴ − 49 is (11b^2 + 7)(11b^2 - 7).
The equation 121b⁴ − 49
To find the Factorization of 121b⁴ − 49.
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What is the factor of a^2-b^2?</h3>
The factor of a^2-b^2 is (a+b)(a-b)
We have write the given equation in the form of a^2-b^2
Therefore the factor of the 121b^4 − 49 is (11b^2 + 7)(11b^2 - 7).
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brainly.com/question/25829061
Answer: There 225 3-digit numbers multiple of 4
1/2 (Base x height) = area
1/2 (4*x)=10
2x=10
X=5
The height is 5 units
The answer would be a because of the time he is at the gym just add and subtract but the answer is a