Answer:
Standard error of mean = 689
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = $28,520
Standard Deviation, σ = $5600
Mean of sampling distribution =
As per Central Limit Theorem, if the sample size is large enough, then the sampling distribution of the sample means follow approximately a normal distribution.
Sample size, n = 66
Since the sample size is large, we can use normal distribution for approximation.
Standard error of mean =
Answer:
5 pints per hour.
Step-by-step explanation:
Morning:
Given:
Number of strawberries packed in every 4 minutes = 3
∴ Number of strawberries packed in every one minute =
So, number of strawberries packed in every 60 minutes =
1 hour = 60 minutes.
So, strawberries are packed at a rate of 45 pints per hour in the morning.
Afternoon:
Number of strawberries packed in every 3 minutes = 2
∴ Number of strawberries packed in every one minute =
So, number of strawberries packed in every 60 minutes =
1 hour = 60 minutes.
So, strawberries are packed at a rate of 40 pints per hour in the afternoon.
Difference between the packing rates is given as:
Morning rate - Afternoon rate = 45 - 40 = 5 pints per hour.
So, she packed 5 more pints in one hour in the morning than in the afternoon.