Answer:
6,25%
Explanation:
Considering that the couple has a trait of sickle cell anemia, we know that both are heterozygous for the disease (Aa) and therefore can have children with the following genotypes:
Parents: Aa X Aa
Children: AA(A x A), Aa(A x a), Aa (a x A) and aa(a x a)
Knowing that sickle cell anemia only occurs in homozygous individuals, the probability for children to have the disease according to each crossing is:
A x A = 1/4 = 25%
A x a = 1/4 = 25%
a x A = 1/4 = 25%
a x a = 1/4 = 25%
The probability of forming each homozygous child (aa) is 1/4 or 25%. Since they are two children, the probability of both having sickle cell anemia is calculated by multiplying the probability of each, so:
1/4 × 1/4 = 1/16 = 0.0625 = 6.25%
It is concluded that the probability of a heterozygous couple for sickle cell anemia to have two children with the disease is 6.25%.
A situation where friction would be desirable is rubbing your hands together to make them warm in the winter time.
Well you know sometimes you see a lot of small bridges that will have weight limit signs. I believe this is really for safety precautions. Keyword: SMALL bridge -
Due to some bridges being small, the materials and strength of the bridge may not can withstand a certain weight. The contents of the vehicle, axels, and wheels, all add to that weight. So there is a very good reason for that to matter.
I hope my somewhat, tied together answer provides just the information you need!
~Brooke❤️
