121 is big enough to assume normality and not worry about the t distribution. By the 68-95-99.7 rule a 95% confidence interval includes plus or minus two standard deviations. So 95% of the cars will be in the mph range
The question is a bit vague, but it seems we're being asked for the 95% confidence interval on the average of 121 cars. The 121 is a hint of course.
The standard deviation of the average is in general the standard deviation of the individual samples divided by the square root of n:
So repeating our experiment of taking the average 121 cars over and over, we expect 95% of the averages to be in the mph range
That's probably the answer they're looking for.
Answer:
-63
Step-by-step explanation:
When solving by substation the answer would be: X= 1 , y= 5
We know
90
∘
=
1
right angle
=
100
g
So
A
∘
=
(
100
90
⋅
A
)
g
Hence by the given condition
B
=
(
100
90
⋅
A
)
=
10
9
A
=
A
+
(
A
9
)
Answer
Answer:
Step-by-step explanation:
1.) 6C4= 15
2.) (1C1)*(6C3)= 20
3.) (2C2)*(6C2)= 15