Answer:
8 and 4
Step-by-step explanation:
i had it
<em><u>The solution is (4, 4)</u></em>
<em><u>Solution:</u></em>
<em><u>Given system of equations are:</u></em>
<em><u>Substitute eqn 2 in eqn 1</u></em>
Make the right side of equation 0
<em><u>Solve by quadratic equation</u></em>
<em><u>Substitute x = 4 in eqn 2</u></em>
y = 2(4) - 4
y = 8 - 4
y = 4
Thus solution is (4, 4)
Answer:
Except k=7, any real number for k would cause the system of equations to have no solution.
Step-by-step explanation:
In general a system of equations can be represented as ax+by=c and dx+ey=f. In order this system of equations to have NO SOLUTIONS a/d=b/a≠c/f. In our example a=6, b=4, c=14, d=3, e=2 and f=k. To apply the formula above, 6/3=4/2≠14/k. Hence k≠7. It can be concluded that except k=7, any real number for k would cause the system of equations to have no solutions.
Just for information, if k=7 the system will have infinitely many solutions.
C by AA- bc 180 degrees in a triangle
