Find a negative real number such that the square of the sum of the number and 5 is equal to 48

How many pounds of candy worth $8 per lb. should be mixed with 100 lb. of candy worth $4 per lb. to get a mixture that can be so

Gwar [14]

Answer:

300 lbs

Step-by-step explanation:

Let x be the number of pounds of candy worth $8 per lb mixed

Now we have total pounds $= 100+x$

Value of the mixture $= 100(4)+8x = 8x+400$

Since 7 per lb to be sold out we get

$\frac{8x+400}{100+x} =7\\8x+400 = 700+7x\\x=300$

300 lbs should be mixed

5 0

2 years ago

Two methods, A and B, are available for teaching Spanish. There is a 70% chance of successfully learning Spanish if method A is

lara [203]

Answer:

0.7671 = 76.71% probability that he was taught by method A

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Person learned Spanish successfully.

Event B: Method A was used.

Probability of a person learning Spanish successfully:

70% of 80%(using method A)

85% of 20%(using method B)

So

$P(A) = 0.7*0.8 + 0.85*0.2 = 0.73$

Probability of a person learning Spanish successfully and using method A:

70% of 80%, so:

$P(A \cap B) = 0.7*0.8 = 0.56$

What is the probability that he was taught by method A?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.56}{0.73} = 0.7671$

0.7671 = 76.71% probability that he was taught by method A

8 0

2 years ago

The points -4 and 5 are plotted on a number line. What is the distance, in units, between the two points?

Anni [7]

The distance between two numbers is the absolute value of their difference.

Note that the order doesn't matter, since the distance between A and B is the same as the distance between B and A, obviously:

$d=|-4-5|=|-9|=9$

$d=|5-(-4)|=|5+4|=|9|=9$

So, the two points are 9 units away.

5 0

2 years ago

If master chief has three and a half cookies, and the arbiter has five and three quarters of a cookie, how many cookies do they

nikklg [1K]

Answer:

$9\dfrac{1}{4}$

$4\dfrac{5}{8}$

Step-by-step explanation:

The master chief has three and a half cookies i.e. $3\dfrac{1}{2} = \dfrac{7}{2}$ numbers of cookies.

Again the arbiter has five and three quarters of a cookie i.e. $5\dfrac{3}{4} = \dfrac{23}{4}$ number of cookies.

Therefore, in total there are $(\dfrac{7}{2} +\dfrac{23}{4} ) = \dfrac{37}{4} = 9\dfrac{1}{4}$ numbers of cookies.

If we divide the total number of cookies in to equal parts and distribute to then then each of them will get $\dfrac{37}{4 \times 2} = \dfrac{37}{8} = 4\dfrac{5}{8}$ numbers of cookies. (Answer)

3 0

2 years ago

How do you do it? What do you take away and do after?

Nuetrik [128]

hi sorry I can't help with that

5 0

2 years ago

Read 2 more answers