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Write a balanced equation for the decomposition of ammonium nitrate to form molecular nitrogen, molecular oxygen, and water. Exp

VARVARA [1.3K]

The unbalanced reaction is

a NH₄NO₃ ⇒ b N₂ + c O₂ + d H₂O

where a, b, c, and d are unknown constants.

Count how many times each element appears on either side of the reaction.

• reactants:

N = 2a, H = 4a, O = 3a

• products

N = 2b, O = 2c + d, H = 2d

Now we solve the system of equations,

2a = 2b … … … [1]

4a = 2d … … … [2]

3a = 2c + d … … … [3]

From [1] we immediately have

a = b

In [2], we get

2a = d

and substituting for d in [3] gives

3a = 2c + 2a

a = 2c

Let c = 1; then

• a = 2×1 = 2

• b = 2

• d = 2×2 = 4

So, the balanced reaction is

2 NH₄NO₃ ⇒ 2 N₂ + O₂ + 4 H₂O

8 0

2 years ago

In Seattle's speech, he states, "Yonder sky has wept tears of compassion on our fathers for centuries untold".This statement is

77julia77 [94]

It is an example of personification because personification is when human traits are give to non human things. Sky's cannot cry.

5 0

2 years ago

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1. A 14-cm tall object is placed 26 cm from a converging lens that has a focal length of 13 cm.

AURORKA [14]

Answer:

a) Please find attached the required drawing of light passing through the lens

By the use of similar triangles;

The image distance from the lens = 26 cm

The height of the image = 14 cm

c) The image distance from the lens = 26 cm

The height of the image = 14 cm

Explanation:

Question;

a) Determine the image distance and the height of the image

b) Calculate the image position and height

The given parameters are;

The height of the object, h = 14 cm

The distance of the object from the mirror, u = 26 cm

The focal length of the mirror, f = 13 cm

The location of the object = 2 × The focal length

Therefore, given that the center of curvature ≈ 2 × The focal length, we have;

The location of the object ≈ The center of curvature of the lens

The diagram of the object, lens and image created with MS Visio is attached

From the diagram, it can be observed, using similar triangles, that the image distance from the lens = The object distance from the lens = 26 m

The height of the image = The height of the object - 14 cm

b) The lens equation is used for finding the image distance from the lens as follows;

$\dfrac{1}{u} + \dfrac{1}{v} = \dfrac{1}{f}$

Where;

v = The image distance from the lens

We get;

$v = \dfrac{u \times f}{u - f}$

Therefore;

$v = \dfrac{26 \times 13}{26 - 13} = \dfrac{26 \times 13}{13} = 26$

The distance of the image from the lens, v = 26 cm

The magnification, M =v/u

∴ M = 26/26 = 1, therefore, the object and the image are the same size

Therefore;

The height of the image = The height of the object = 14 cm.

5 0

2 years ago

What will be the change in momentum caused by a net force of 120N acting on an object for 2 seconds?

In-s [12.5K]

Answer:

240 Ns

Explanation:

The momentum of an object is the product of its mass and its velocity:

$p=mv$

where m is the mass of the object and v its velocity.

According to Newton's second Law of motion, the change in momentum of an object is related to the force applied by it by the equation:

$F=\frac{\Delta p}{\Delta t}$

where

F is the force exerted on the object

$\Delta p$ is the change in momentum

$\Delta t$ is the time elapsed

In this problem:

F = 120 N is the force exerted on the object

$\Delta t=2 s$ is the time elapsed

Therefore, the change in momentum of the object is:

$\Delta p=F\Delta t=(120)(2)=240 Ns$

7 0

2 years ago

How do the following factors affect the resistance of a wire?

Alborosie

The temp would affect the length of the wire
the length would affect how much support there is as well as the diameter of the wire

4 0

2 years ago