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2 years ago

4x + 3y = 6 3x + 5y = -1 Solve the simultaneous equations. y= z=

Mathematics

1 answer:

Kisachek [45]2 years ago

4 0

Answer:

x=3, y= -2

Step-by-step explanation:

Multiplying :

(4x+3y =6)*-3

(3x+5y =-1)*4

-12x -9y= -18

12x+20y= -4

Add the equations

20y-9y = -4-18

11y = -22

y= -22/11 = -2

3x +5* -2= -1

3x -10 = -1

3x = 10-1

x= 9/3 =3

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3x+1y=6 2x-1y=-1 plz helpllllllllll

Gwar [14]

Answer:

x=1 y=3

Step-by-step explanation:

3x+y=6 is the same as y=6-3x

2x-y=-1 is the same as y=2x+1

set them equal to each other

6-3x=2x+1

5x=5

x=1

substitute the value of x into either equation

y=2(1) +1

y=3

4 0

2 years ago

Evaluate 4.7 j−6.8k when j=5 and k=3

oksano4ka [1.4K]

Answer:

3.1

Step-by-step explanation:

ok so

4.7j-6.8k J=5 k=3 plug in the values

4.7(5)-6.8(3)

23.5-20.4

3.1

8 0

1 year ago

Read 2 more answers

In the diagram shown, sp pt pm st ps=13 and sm=5

pogonyaev

What diagram???
Sorry but there’s no pic so I can’t help you

5 0

2 years ago

2 + 2j = 6 what does J equall?

nordsb [41]

Answer:

Step-by-step explanation:

2+2(2)=6

2(2)=4

4=4

4 0

2 years ago

Read 2 more answers

A rectangular garden must have a perimeter of 145 feet and an area of at least 1100 square feet. Describe the possible lengths o

marta [7]

Answer:

The approximate length of the garden is at least 22 feet and at most 51 feet.

Step-by-step explanation:

A rectangular garden must have a perimeter of 145 feet.

Let x feet be the lengths of the garden. Then the width of the garden can be found using the perimeter:

$P=2(\text{Length}+\text{Width})\\ \\145=2(x+\text{Width})\\ \\\text{Width}=72.5-x$

The area of the garden is

$A=\text{Length}\cdot \text{Width}\\ \\A=x\cdot (72.5-x)$

The area must be at least 1,100 square feet, then

$x(72.5-x)\ge 1,110\\ \\72.5x-x^2-1,100\ge 0\\ \\x^2-72.5x+1,100\le 0$

Solve this quadratic inequality:

$D=(-72.5)^2-4\cdot 1,100=856.25\\ \\\sqrt{D}=25\sqrt{1.37}\\ \\x_1=\dfrac{72.5-25\sqrt{1.37}}{2}\approx 22\\ \\x_2=\dfrac{72.5+25\sqrt{1.37}}{2}\approx 51\\ \\(x-22)(x-51)\le 0\\ \\x\in [22,51]$

3 0

2 years ago