Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
18.84
Step-by-step explanation:
The formula for circumference is 2(pi)r, I think. The radius is 3. 3 times 2 is 6. 6 times 3.14 is around 18, I think.
The area of the trapezoid would be 48
The pathway is 8.46 yards.
<h3>How to find the length of the pathway?</h3>
To find the length of the pathway, it is required to find how long is the diagonal line from one corner of the herb garden to the opposite corner. As shown in the image attached.
The general formula for this is:
- d = a√2 or diagonal = side√2
Let's apply this formula:
- d= 6 √2
- d= 6 x 1.41
- d= 8.46 yards
Learn more about yards in: brainly.com/question/14516546
