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2 years ago

What is the value of x in the equation

Mathematics

2 answers:

VLD [36.1K]2 years ago

7 0

Answer:

5+3/10 = 4/5 X=5

Step-by-step explanation:

8/10 DIVIDED BY 2 = 4/5

aleksley [76]2 years ago

5 0

Answer:

Step-by-step explanation:

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Vlada [557]

15 x 20 and 10 x 30 hope this works

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2 years ago

Which angles are corresponding angles?

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Its ONL and PQS
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2 years ago

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5x+5y=-30 find the x and y intercept

Masja [62]

<em>The x and y intercept of 5x + 5y = -30 are (-6, 0) and (0, -6) respectively.</em>

<h2 /><h2>Explanation:</h2>

The Standard Form of the equation of a line is given by:

$Ax+By=C \\ \\ A,B,C \ Real \ Constants \ and \ A>0$

So:

$5x+5y=-30$

is written in Standard Form. The x and y intercepts are:

$x-intercept: \ (x,0) \\ \\ y-intercept: \ (0,y)$

So:

FOR X-INTERCEPT:

$Let's \ set: \\ y=0 \\ \\ 5x+5(0)=-30 \\ \\ Isolating \ x: \\ \\ 5x=-30 \\ \\ x=-\frac{30}{5} \\ \\ \boxed{x=-6}$

FOR Y-INTERCEPT:

$Let's \ set: \\ x=0 \\ \\ 5(0)+5y=-30 \\ \\ Isolating \ x: \\ \\ 5y=-30 \\ \\ y=-\frac{30}{5} \\ \\ \boxed{y=-6}$

Finally,<em> the x and y intercept of 5x + 5y = -30 are (-6, 0) and (0, -6) respectively.</em>

<h2>Learn more:</h2>

Parallel lines: brainly.com/question/12169569

#LearnWithBrainly

6 0

2 years ago

Use the quadratic formula to solve x2 + 9x + 10 = 0.<br> What are the solutions to the equation?

vampirchik [111]

Answer:

$\large\boxed{x=\dfrac{-9\pm\sqrt{41}}{2}}$

Step-by-step explanation:

$\text{The quadratic formula of}$

$ax^2+bx+c=0$

$\text{If}\ b^2-4a0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\=========================================$

$\text{We have}\ x^2+9x+10=0\\\\a=1,\ b=9,\ c=10\\\\\text{substitute:}\\\\b^2-4ac=9^2-4(1)(10)=81-40=41>0\qquad _{\text{two solutions}}\\\\\sqrt{b^2-4ac}=\sqrt{41}\\\\x=\dfrac{-9\pm\sqrt{41}}{2(1)}=\dfrac{-9\pm\sqrt{41}}{2}$

5 0

2 years ago

Read 2 more answers

What are the coordinates of the point on the directed line segment from (1,-5) to

Black_prince [1.1K]

Answer:

Q (2.5, -4)

Step-by-step explanation:

Let A (1, -5), C = (10, 1), find Q (x, y), so that AQ:QC = 1:5

AQ = (x - 1, y + 5)

QC = (10 - x, 1 - y)

AQ:QC = 1:5

so 5*AQ = QC

5(x - 1) = (10 - x)

5(y + 5) = 1 - y

Solve them:

5x - 5 = 10 - x

6x = 15

x = 15/6 = 2.5

5y + 25 = 1 - y

6y = -24

y = -24/6 = -4

Then answer is Q (2.5, -4)

6 0

1 year ago