By the remainder theorem of polynomial division, the complete equation is f(-3) = 11
<h3>How to complete the blanks?</h3>
The equation is given as:
f(x)/x + 3
Set the divisor to 0
x + 3 = 0
Solve for x
x = -3
Given that the quotient has a remainder of 11.
It means that:
f(-3) = 11
Hence, the complete equation is f(-3) = 11
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Answer:
The probability is
Step-by-step explanation:
We can divide the amount of favourable cases by the total amount of cases.
The total amount of cases is the total amount of ways to put 8 rooks on a chessboard. Since a chessboard has 64 squares, this number is the combinatorial number of 64 with 8,
For a favourable case, you need one rook on each column, and for each column the correspondent rook should be in a diferent row than the rest of the rooks. A favourable case can be represented by a bijective function with A = {1,2,3,4,5,6,7,8}. f(i) = j represents that the rook located in the column i is located in the row j.
Thus, the total of favourable cases is equal to the total amount of bijective functions between a set of 8 elements. This amount is 8!, because we have 8 possibilities for the first column, 7 for the second one, 6 on the third one, and so on.
We can conclude that the probability for 8 rooks not being able to capture themselves is
Answer:
1/3
Step-by-step explanation:
I think this is 1/3 because it is a ratio of successful outcomes to total number of outcomes..
Ex. Rolling a 6 sided dice.. you roll a 5... it would be 1/6.
Hope that makes sense.
Factors of 180:
1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 30, 36, 45, 60, 90, 180.
Factors of 270:
1, 2, 3, 5, 6, 9, 10, 15, 18, 27, 30, 45, 54, 90, 135, 270.
What are the factors of both 270 and 180?
1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45, 90.
Which one of these would give us the greatest amount of baskets possible?
Answer: 90 baskets.
I hope this helped you! c: